The difference of y and 5 is at the most 20

In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0

3 years ago

Find the diameter of the circle with the given circumference use 3.14 C=18

algol [13]

The formula for the circumference of a circle is pi * r * 2

First we solve for r (the radius)
pi*r*2 = C
pi*r*2 = 18

Divide 18 by 2
pi*r = 9

Then divide 9 by 3.14
pi= 9/3.14 which is 2.866

The diameter is 2 times length of the radius so multiply 2.866 by 2
The diameter is about 5.732
(And you can round of course)

Hope that helped

3 0

3 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago

How do I write this as an equation

Lana71 [14]

Let x be the number of children
Let y be the number of adults

x + y = 4
4x + 7y = 19

5 0

3 years ago

The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an al

natali 33 [55]

Answer:

a. k = 94

b. Every 94th individual.

Step-by-step explanation:

Systematic sampling is a type of probability sampling where a random sample is selected from a large population by first dividing the whole population into n groups and selecting every $\frac{N}{n}=k^{th}$ individual from each group.

The population size is: N = 6584.

The sample size is, n = 70

The number groups is, 70.

Each consisting of $\frac{6584}{70}=94.057\approx 94$ individuals.

(a)

The kth individual will be the 94th individual from each group.

Thus, k = 94.

(b)

The individuals who will be administered the survey are the 94th individual of all the 70 groups.

3 0

3 years ago