5 poles will be in 50 yards because 10 x 5 = 50
Hope helps-Aparri
You haven't listed the possible solutions, so in the immediate present I can help only by suggesting that you try solving this system and checking your own answers thru subst. into the given equations.
Please be sure to use "^" to indicate exponentiation, as shown below:
<span>4x2 + 9y2 = 72 should be 4x^2 + 9y^2 = 72 (this is the eq'n of an ellipse)
x - y2 = -1 should be x - y^2 = -1 (this is the equation of a parabola)
We must eliminate either x or y. I will solve the 2nd equation for y^2 and subst. the result into the first eq'n.:
y^2 = x+1. Subst. this into the first equation,
</span>4x^2 + 9y^2 = 72 becomes 4x^2 + 9(x+1) = 72.
Expanding, 4x^2 + 9x + 9 = 72, or 4x^2 + 9x - 63 = 0
We must solve this quadratic equation to obtain the x-coordinates of possible solutions of the original system of equations.
-9 plus or minus 33
After some work, we get x = ------------------------------
8
So x = 24/8 = 3, or x = -42/8 = -5 1/4 or -21/4
Check out x=3. We already have the relationship y^2 = x+1. If x = 3, then y^2 = 3+1 = 4, and y is plus or minus 2.
Two possible solutions of the original set of equations are thus (3,2) and (3,-2). You MUST check both solutions thru substitution to determine whether they satisfy the original equations or not.
Answer:
3...You are kidding right?
Step-by-step explanation:
Answer:
x=12 ADB= 56 BDC= 54
Step-by-step explanation:
ADB and BDC are complementary, so they add up to 90 degrees. In other words ADB+BDC= 90 So I can input my knowns into the equation
(3x+10) + (4x-4) = 90
I combined like terms to give me 7x+6=90
Then I subtract 6 from both sides giving me 7x=84
Last I divide 7 on both sides. x=12
Then I input the x (12) into the equation and solve it from there
3(12)+10 and 4(12)-4
3(12)+10=56
4(12)-4=54
. . . I think. Hope this helps!