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saul85 [17]
3 years ago
11

A rectangle is 1 cm more than twice its width. Find the dimensions of the rectangle if it’s area is 45cm.

Mathematics
1 answer:
spayn [35]3 years ago
7 0

Answer:

10*4.5

length=10cm, width=4.5cm

Hint: 2b^2+b-45=0

I hope it will be useful.

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A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
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Answer:

There can be at most 12 attendees in a corporate team-building event.

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Let x denotes number of attendees in a corporate team-building event.

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Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

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3 years ago
In a certain triangle the longest side is twice as long as the shortest side and the shortest side is 4 inches shorter than midd
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Answer:

24 inches

Step-by-step explanation:

Let the longest side be x, the middle side be y and the shortest side be z

Rest is in the attached file

5 0
3 years ago
A rectangular tank with a square​ base, an open​ top, and a volume of 8 comma 7888,788 ft cubedft3 is to be constructed of sheet
Vlad [161]

Answer:

  26 ft square by 13 ft high

Step-by-step explanation:

The tank will have minimum surface area when opposite sides have the same total area as the square bottom. That is, their height is half their width. This makes the tank half a cube. Said cube would have a volume of ...

  2·(8788 ft^3) = (26 ft)^3

The square bottom of the tank is 26 ft square, and its height is 13 ft.

_____

<em>Solution using derivatives</em>

If x is the side length of the square bottom, the height is 8788/x^2 and the area is ...

  x^2 + 4x(8788/x^2) = x^2 +35152/x

The derivative of this is zero when area is minimized:

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  x = 26

_____

As the attached graph shows, a graphing calculator can also provide the solution.

5 0
3 years ago
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