Answer:
a) The bullet hits the ground after 64 seconds.
b) The bullet hits the ground 113,511.7 feet away.
c) The maximum height attained by the bullet is of 16,384 feet.
Step-by-step explanation:
Equations of motion:
The equations of motion for the bullet are:


In which
is the initial speed and
is the angle.
Initial speed of 2048 ft/s at an angle of 30o to the horizontal.
This means that
.
So


(a) After how many seconds will the bullet hit the ground?
It hits the ground when
. So



16t = 0 -> t = 0 or t - 64 = 0 -> t = 64
The bullet hits the ground after 64 seconds.
(b) How far from the gun will the bullet hit the ground?
This is the horizontal distance, that is, the x value, x(64).

The bullet hits the ground 113,511.7 feet away.
(c) What is the maximum height attained by the bullet?
This is the value of y when it's derivative is 0.
We have that:




At this instant, the height is:

The maximum height attained by the bullet is of 16,384 feet.