Can someone help me with this math problem ?? Pls it’s for my final !
1 answer:
Answer:
221.87 feet
Step-by-step explanation:
Given that,
A 525 ft cable runs from the top of an antenna to the ground.
The angle of elevation made by the ground to the top of an antena 25°
We need to find the height of the antenna.
Using trigonometry,
Hypotenuse, H = 525 ft
θ = 25°
So,
So, the height of the antenna is equal to 221.87 feet.
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Answer:
2.45c + 1.65c = 4.12 + 0.75
Step-by-step explanation:
To write an equation to find the value for c, we need to declare what c is first.
c = price of fruit
2.45c + 1.65c = 4.12 + 0.75
Now we multiplied c to 2.45 and 1.65 and added them together, because whatever the value of c is will give us the equivalence of the sum of 4.12 + 0.75.
Now to check if the equation is right, let's solve for c.
2.45c + 1.65c = 4.12 + 0.75
4.1c = 4.87
Now to get the value of c, we divide both sides of the equation by 4.1.
c = 1.19
Now let's substitute the value of c in the equation to see if we got it right.
2.45(1.19) + 1.65(1.19) = 4.12 + 0.75
2.92 + 1.96 = 4.87
4.87 = 4.87
Therefore concluding that the value of c is 1.19.
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.