The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
As we travel from (-2, p) to (2, 2p+1), x increases by 4 and y increases by p+1. Note that -2 + 4 = 2 (which is correct), and that p + (p+1) = 2p+1 (which is also correct).
p+1
Thus, the slope of this line is m = rise / run = -------- = 9
4
Then p + 1 = 36, and p = 35.
10+ x/6 i believe this is the answer
Rotational symmetry = 360 / # sides
rotational symmetry = 360 / 9
rotational symmetry = 40 degrees
x+y-z+w = 10--------(1)
x+3y-4z+5w=26------(2)
x+4y-7z+7w = 37-------(3)
x+2y-3z+6w = 22--------(4)
Subtract equation (1) from (2)
x+3y-4z+5w - (x+y-z+w) = 26 - 10
2y + -3z - 4w = 16-----------------------------(5)
Subtract equation (1) from (3)
