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BigorU [14]
3 years ago
6

Please answer this question step by step with formula.

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

Net price = $191.25

Discount Price = $33.75

Step-by-step explanation:

Cost of one pen = $0.50

Cost of 200 pen = 200 × 0.50 = $100

Cost of one pad =$0.70

Cost of 150 pads = 150 × 0.70 = $105

Cost of one pencil = $0.20

Cost of 100 pencils = $20

Total cost of the order = 100 + 105 + 20 = $225

Discount % = 15% of 225

Discount price = ( 15% × 225) = $33.75

Total amount after discount = 225 - 33.75 = $191.25

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Step-by-step explanation:

First go to THE UNITED STATES

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Is (5, 10), (-8, 3), (-1, 7), (-5, 10) A Function ?
ankoles [38]

Answer:

Step-by-step explanation:

Notice that the inputs {5, -8, -1, -5} are all different.  So we can immediately conclude that this is a function.

If the inputs were {5, -8, -1, 5}, this would not be a function, as the same input value (5) would result in two different outputs.

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3 years ago
I am of a number. If you multiply my number by 4, add -4 to the product, and then take 1/3 of the sum, the result is -6. Find my
Bumek [7]

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Do you know what the word avionics is? If so define it, if not look it up and define it. How do you think robots will play an im
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Answer:

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Step-by-step explanation:

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2 years ago
Use the chain rule calculate dw/dr , dw/ds and dw/dt
Liono4ka [1.6K]

Answer:

\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}, \frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}, \frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}

Step-by-step explanation:

We proceed to derive each expression by rule of chain. Let be w = \ln (x+2\cdot y + 3\cdot z), x = r^{2}+t^{2}, y = s^{2}-t^{2} and z = r^{2}+s^{2}:

\frac{dw}{dr} = \frac{\frac{dx}{dr}+2\cdot \frac{dy}{dr} +3\cdot \frac{dz}{dr}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{dr} = 2\cdot r

\frac{dy}{dr} = 0

\frac{dz}{dr} = 2\cdot r

\frac{dw}{dr} = \frac{8\cdot r}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (1)

\frac{dw}{ds} = \frac{\frac{dx}{ds}+2\cdot \frac{dy}{ds} +3\cdot \frac{dz}{ds}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{ds} = 0

\frac{dy}{ds} = 2\cdot s

\frac{dz}{ds} = 2\cdot s

\frac{dw}{ds} = \frac{10\cdot s}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (2)

\frac{dw}{dt} = \frac{\frac{dx}{dt}+2\cdot \frac{dy}{dt} +3\cdot \frac{dz}{dt}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{dt} = 2\cdot t

\frac{dy}{dt} = -2\cdot t

\frac{dz}{dt} = 0

\frac{dw}{dt} = -\frac{2\cdot t}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (3)

7 0
2 years ago
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