9 more than y is an expression so it would be 9+y
Answer:
x^2-x+5
Step-by-step explanation:
(f-g)(x)=f(x)-g(x)
= (x^2 + 3) - (x - 2) (Don’t forget the -1 multiplies to the x AND -2
= x^2 + 3 - x + 2
=x^2-x+5
If m ACD = 30 => m DCB = 60.
In triangle ACD:



AC^{2}+CB^{2}=AB^{2} => AB=

=32.
=> P=16+32+

=48 +

.
Answer:
Dimensions of the rug = 13 ft × 26 ft
Step-by-step explanation:
Dimensions of the room = 21 ft × 34 ft
Area of the room = 21 × 34 = 714 ft²
Cynthia wants to leave a uniform strip of floor around the rug.
Let the width of the rug = x ft
Then the dimensions of the rug will be = (21- 2x)ft × (34 - 2x)ft
Area of the rug = (21 - 2x)×(34 - 2x) square feet
338 = (21 - 2x)×(34 - 2x)
338 = 714 - 68x - 42x + 4x²
4x² - 110x + 714 - 338 = 0
4x² - 110x + 376 = 0
2x² - 55x + 188 = 0
2x² - 47x - 8x + 188 = 0
x(2x - 47) - 8(x - 47) = 0
(x - 4)(2x - 47) = 0
x = 4, 
For x = 23.5 area of the rug will be negative.
Therefore, x = 4 ft will be the width of the rug.
Dimensions of the rug will be 13 ft × 26 ft.