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mash [69]
3 years ago
12

What is the slope of the line.

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

the image inserted is a blank black. there is no graph.

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A professional basketball court is in the shape of rectangle. It is 50 feet wide and 84 feet long.A player runs one time around
JulsSmile [24]
The court is the shape of a rectangle, so that means 2 sides are 50 feet and 2 sides are 84 feet
 if a player ran around the edge he ran 50 + 50 + 84 + 84 = 268 feet total

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Fantom [35]

Answer:

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8 0
3 years ago
I forgot how to do this.... can somebody help?
slamgirl [31]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}



\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D  = -3

\bf f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}\implies f(x)={{  -2}}(\mathbb{R})^{{{  1}}x-{{  3}}}-{{3}}\\\\\\ f(x)={{  -2}}(3)^{{{  }}x-{{  3}}}-{{3}}
3 0
4 years ago
A) 10=4+3(t+5) b) 28=4+3(t+5) c) 0=16+4(m-6)
Angelina_Jolie [31]

Answer:

t=-3  t=3 m=2

Step-by-step explanation:

a. 10=4+3(t+5)

3xt      3x5

10=4+3t+15

4+15

10=3t+19

-19    -19

-9=3   -9/3

-3=t

b. 28=4+3(t+5)

3xt  3x5

28=4+3t+15

4+15

28=3t+19

-19       -19

9=3t   9/3

3=t

c. 0=16+4(m-6)

4xm 4x-6

0=16+4m-24

16-24

0=4m-8

+8    +8

8=4m    8/4

2=m

5 0
3 years ago
DOMAIN is the set of all input value while range is the set of all
Triss [41]
Range is the set of all output values.
8 0
3 years ago
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