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ANTONII [103]
3 years ago
6

Write the word sentence as and equation or inequality A number divided by 7 equals 14

Mathematics
1 answer:
Lerok [7]3 years ago
8 0
<h2>Firstly, we let for the number to be any number or letter.</h2>
  • So let the number be (x)

Step-by-step explanation:

The above pictures shows working.

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Can someone help me here​
bearhunter [10]

Answer:

1.

Step-by-step explanation:

1. sin 241 = sin(61 + π) = -sin61 = -t^(1/2)

2. sin^2 + cos^2 =1, cos 61= (1-t)^(1/2)

3. [2sin^2 (x)sin(x) +2cos^2 (x)sin(x)]/2cos(x) = 2sin(x) / 2cos(x) = tan(x)

4. tan (x), x do not equal to (π/2 +or- kπ)

x do not equal to 90,270。

3 0
2 years ago
Nandeville and Henningsburg are 75 miles apart. On a map, the two cities are 5 inches apart. How many miles does 1 inch represen
soldier1979 [14.2K]

Answer:

5 miles

Step-by-step explanation:

because when u divide 10 and 2 you will get 5

6 0
2 years ago
Mathematical induction, prove the following two statements are true
adelina 88 [10]
Prove:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}
____________________________________________

Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}

Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}
3 0
3 years ago
X+2/3 + x-1/4=x please answer. I need it b4 2moro
Dmitrij [34]

Answer:

-5/12

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

7 0
2 years ago
Read 2 more answers
The area of the right triangle shown is 24 square feet.
Liula [17]

Answer:

A, 0.5(x)(x+2)=24, D, x²+2x-48=0, and E, x²+(x+2)²=100

Step-by-step explanation:

A and D are correct because they simply involve the Area of a Triangle formula. A has the formula in the same format, but D has the 0.5 divided from by both sides.

E, on the other hand, uses the Pythagorean theorem to solve for both legs.

5 0
3 years ago
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