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olga55 [171]
3 years ago
15

Which property proves triangles are congruentttt

Mathematics
1 answer:
Pepsi [2]3 years ago
7 0
Two triangles are congruent if and only if all corresponding angles and sides are congruent.

ANSWER: AAS
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Which expression is NOT equivalent to 12 x -3 2/3
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Add then multiply b through,  e to f, hopethsie helps
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Can someone please answer. There is one problem. There's a picture. Thank you!
schepotkina [342]
Sin(12) ≈ 0.208

  cos(x) = 0.208
  cos(x) = sin(12)
cos(78) = sin(12)

  cos(12) ≈ 0.978
  cos(68) ≈ 0.375
cos(102) ≈ -0.208
  cos(78) ≈ 0.208

The answer is D.
4 0
4 years ago
Jada measured the height of a plant in a science experiment and finds that, to the nearest 1/4 of an inch, it is 4 3/4 inches.
Natalka [10]

Answer:

I dont know

Step-by-step explanation:

sorrryy

5 0
3 years ago
Read 2 more answers
PLEASE help me and PLEASE show the work PLEASE.
Dafna1 [17]

20(4×-2)

________

(4 - (-2))²

simplified;

20(-8)

_____

(6)²

simplified;

-160

______

36

simplified;

-4 16/36

simplified;

-4 4/9


3 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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