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aleksley [76]
3 years ago
5

A builder had been asked to lay an octagonal patio using square paving slabs. To do this, he cuts some of the bricks in half dow

n the diagonal. Each paving slab is 1m wide. What will the perimeter of the patio be
Mathematics
1 answer:
Orlov [11]3 years ago
7 0
Assuming you want an expression for the possible total area of the patio: if "completed" would be a rectangle of dimensions n, m: each must be >=3 to allow for octagonal corners. But each of the 4 corners must be missing, that's diagonals comprising (1/2)a^2, (1/2)b^2, (1/2)c^2, and (1/2)d^2, where a,b,c, and d must be variously limited and co-limited so as to allow at least 1 linear side of the original rectangle to be exposed. So A = (n*m)-(1/2)a^2-(1/2)b^2-(1/2)c^2-(1/2)d^2 as an expression.
Now, imagine replicating your possible (potentially irregular) octagons onto a plane and juxtaposing them so as to create a paved network. What geometric properties might such a network have? You now have a miniscule idea what nature does with silicate networked minerals, except that takes place in 3-D, with tetrahedra of SiO4 .
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Niklas takes a dose of 25 micrograms of a certain supplement each day. The supplement has a half life of 4 hours, meaning that 1
MrRa [10]

Answer:

The amount of the supplement in Niklas' body immediately after the 12th dose is 4.30 micrograms.

Step-by-step explanation:

Half life is the time required for an element to decay into half of its initial size. The supplement has a half life of 4 hours means that it decay to half of its size every 4 hours. Therefore there are 6 stages of division in a day.

i.e     \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} × \frac{1}{2} =  \frac{1}{64}

The amount of the supplement in Niklas' body after the first dose (first day) can be determined by;

                   = \frac{1}{64} × 25

                  = 0.390625 micrograms

He used the supplement daily for 12 days (12th dose), but the amount of the supplement in his body immediately after the 12th dose would be;

                 amount in his body per day × number of period for complete decay

                   = 0.390625 × 11

                  = 4.296875

The amount of the supplement in Niklas' body immediately after the 12th dose is 4.30 micrograms. This is because immediately after the 12th dose, the supplement has not reach its half life.

3 0
3 years ago
Any base (except 0) raised to the zero power is equal to that number or base.
kap26 [50]
True.
Example: 34^0 is 34
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3x + 5y= -5 in standard form
melomori [17]

Answer:

y= \frac{3}{5} x-1-

Step-by-step explanation:

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Which expression is equivalent to 5p2+ 3p2 - 6p?
melomori [17]

Answer:

is c or d i think

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PLEASE IS DUE IN A FEW MINUTES..
hjlf
Looks like you are screwed good luck:)
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