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marissa [1.9K]
3 years ago
13

Simplify 6(-5n + 7 thank you

Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0

Answer:

-30n + 42

Step-by-step explanation:

6( -5n + 7)

-30n + 42

Hope this helps!

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7 0
3 years ago
PLZ HELP ME!!!! I NEED THE ANSWER QUICK SO IM GIVING BRAINLIEST TO THE FASTEST AND BEST ANSWER.
geniusboy [140]

Answer:

f(x) = 8(1/2)^x.

Step-by-step explanation:

According to the graph, there is a point at (0, 8) and (1, 4).

That means that when x = 0, y = 8.

8 = a(b)^0

1a = 8

a = 8

That means that a = 8, and when x = 1, y = 4.

4 = 8(b)^1

4 = 8b

8b = 4

b = 4/8

b = 1/2

So, f(x) = 8(1/2)^x.

Hope this helps!

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3 years ago
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nikdorinn [45]

Answer:

the first one is a lie

Step-by-step explanation:

caf is more 45 degrees than 25

7 0
2 years ago
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away
Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

\triangle ABD\sim \triangle ECD

\frac{AB}{EC}=\frac{BD}{CD}

Substitute the values

\frac{AB}{1.45}=\frac{31.65}{5.45}

AB=\frac{31.65\times 1.45}{5.45}

AB=8.42m

Hence, the height of the tree=8.42 m

6 0
3 years ago
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

7 0
3 years ago
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