Answer:
where are the expressions??
There’s no “shaded region” so below it’s just the area value.
AD x CD = Area
40 x 30 = 1200
If it they travel at the same speed then acceleration will be 0
Using the equation s= ut + 1/2 a t ^2
Since a is 0
S= ut
From this we can form simultaneous equations
At Original speed
280=ut
Making the time t the subject t= 280/u
At new speed
280=(u+5) (t-1)
Again making time t the subject
t= 280/(u+5) +1
Set equations equal to each other
280/u = 280/(u+5) +1
Get rid of fractions by multiplying everything by denominators (u)(u+5)
(u)(u+5) (280/u) = (u)(u+5) (280/(u+5)) + (u)(u+5)
Cancel terms and simplify to get to
280(u+5) = 280u + u(u+5)
Expand and Solve
280u + 1400 = 280u + u^2 + 5u
u^2 + 5u - 1500= 0
Factorise
(u + 40 ) (u - 35)
Therefore u = -40 or 35
Speed cannot be negative as travelling to a place hence the spited has to be 40km/h
Answer:
Graph (1)
Step-by-step explanation:
This question is incomplete: find the figures for this question in the attachments.
Given function is,
f(x) =
f(1) = = 3
f(2) =
f(3) = = 12
f(4) = = 24
f(5) = = 48
Table for the points on the graph is,
x 1 2 3 4 5
f(x) 3 6 12 24 48
If we plot these points given in the table, we get the graph which matches to the graph given in option (1).
Therefore, Graph (1) will be the answer.