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nata0808 [166]
3 years ago
7

Oil is pumped into a tank at a rate of Q(t)=45-t gallons per minute where time is t is measured in minutes how many gallons are

in the tank after 30 minutes
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

15 gallons

Step-by-step explanation:

Given that:

Pumping rate is modeled by the equation :

Q(t)=45-t gallons per minute ; where t is in minutes

Number of gallons in tank after 30 minutes ;

Q(t)=45-t

Q(30) = 45 - 30

Q(30) = 15

Hence, Number of gallons in tank after 30 minutes is 15 gallons

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\displaystyle\frac{\text{Displacement}}{\text{Time}}

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2) 0.005 s

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y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}

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