Answer:
θ = 60°
Step-by-step explanation:
The cross sectional area of the trapezoid shape will be that of a trapezoid with bases of 10 cm and (10 cm + 2·(10 cm)·cos(θ)) and height (10 cm)·sin(θ).
That area in cm² is ...
A = (1/2)(b1 +b2)h = (1/2)(10 + (10 +20cos(θ))(10sin(θ)
A = 100sin(θ)(1 +cos(θ))
A graphing calculator shows this area to be maximized when ...
θ = π/3 radians = 60°
_____
<em>A</em> will be maximized when its derivative with respect to θ is zero. That derivative can be found to be 2cos(θ)² +cos(θ) -1, so the solution reduces to ...
cos(θ) = 1/2
θ = arccos(1/2) = π/3
Answer:
That would be 0.87
Step-by-step explanation:
Is that the answer you wanted...?
Answer:
1
Step-by-step explanation:
2+2=4
4-3=1
You would use the SSS, ASA, AAS, RHS theorems to prove two triangles to be congruent.
Answer:
Step-by-step explanation
Let the sales be represented by x
Amount made from no of hours worked = $14 × 37.5 hours=$525
Sales made = 6% of x=0.06x
Total = 0.06x+$525=$733.50
0.06x=733.50-$525=$208.5
x=$3,475