Question

PLS HELP ME WITH THIS EQUATION! Find X2%7Dx%20-%204x" id="TexFormula1" title="{3}^{2}x - 32 = {2}^{2}x - 4x" alt="{3}^{2}x - 32 = {2}^{2}x - 4x" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$3x^{2} -32=2x^{2} -4x\\3x^{2} -2x^{2} +4x-32=0\\x^{2} +4x-32=0\\x^{2} -4x+8x-32=0\\x(x-4)+8(x-4)=0\\(x-4)(x+8)=0\\x-4=0 \ or\ x+8=0\\x=4\ or\ x=-8$