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Schach [20]
3 years ago
7

David canoes 20km downstream in 2.5 hours his return trip takes 4 hours find the rate of his current. A 1.5 km/h B 1 km/h C 0.5

km/h D 2.5 km/h
Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

1.5 km/hour

Step-by-step explanation:

d is the David's speed in still water

c is the speed of the current

Going with the current, he travels d+c km per hour.

Going against the current, he travels d-c km per hour.

d+c = (20 km)/(2.5 hours) = 8 km/hour

d-c = (20 km)/(4 hours) = 5 km/hour

Add the equations to eliminate the c terms

d+c = 8

d-c = 5

----------

2d = 13

d = 6.5 km/hour

c = 8-d = 1.5 km/hour

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3 hours

Step-by-step explanation:

15 workers * 7 hours = 105 worker hours

105 worker hours / 35 workers = 3 hours  

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Eighteen oranges are packaged in 3 containers. How many oranges are packaged in 7 containers?
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Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
3 years ago
Archie completed the 0.33 meter course in 2 minutes. How far would he travel in 3 minuets?
svet-max [94.6K]

I believe you can just divide 0.33/2 to get how many meters he can run in 1 minute and then times it by 3, to get how far he can travel in 3 minutes

0.33/2=0.165

0.165*3= your answer

8 0
3 years ago
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