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Otrada [13]
3 years ago
10

.If you travel for 18 hours a distance of 7,794 miles, what was the speed that you traveled per hour

Mathematics
1 answer:
madam [21]3 years ago
5 0

Answer:

433 mph

Step-by-step explanation:

Speed = Distance/Time = 7,794/18 = 433 mph

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3 years ago
The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

a_y ^ 3 = (a_xk) ^ 3

So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



4 0
3 years ago
A student is solving the system of equations below. In which line is a mistake first made?
AlexFokin [52]

Answer:

line 1

Step-by-step explanation:

because

3x + 2y + z = 11 ➡ z = 11 - 3x - 2y

3x and 2y must change sign when transfer to other sid eof equation

5 0
3 years ago
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