All categories

3 years ago

38 - 8 ÷ 3 - 3 -7 + 4 + 16

Mathematics

1 answer:

Umnica [9.8K]3 years ago

7 0

Answer:

45.33333333333

Step-by-step explanation:

You might be interested in

Name a real life situation in which you would need money to divide

oee [108]

Answer:

You and 9 friends all made a bake sale and profited 100 dollars. How much money should you and each friend get.

ANSWER 100/ 9 friends + you

= 100/10

= $10

Step-by-step explanation:

5 0

3 years ago

ASAP: I need as soon as possible with this question I have taken a picture of. If you could tell me how to do it and the answer,

VladimirAG [237]

Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

$tan 14 = \frac{h}{x}$ (1)

$tan 47 = \frac{h}{x - 386}$ (2)

from (1) h = xtan14

substitute in (2) tan 47 = $\frac{xtan14}{x - 386}$

solve for x tan47(x - 386) = xtan14

1.07x - 413.9 = 0.25x

1.07x - 0.25x = 413.9

0.82x = 413.9

x = 413.9/0.82

x = 504.76 ft

2.- Calculate h

h = 504.76 tan 14

h = 125.85 ft = 126 ft

4 0

3 years ago

Simplify with distributive property: 3(4 - 8x)

Lana71 [14]

Answer:

12-24x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.