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ivolga24 [154]
3 years ago
10

Pleaseeeeeeeeeeeee help

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

90

Step-by-step explanation:

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Which of the following is most likely to be a relative maximum for this graph? the points are (-1,0) (2,0) and (4,0) A. (0.5, -8
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The correct answer is B. (3,4)

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4 years ago
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Use unit rate to find the unknown value 16/32 equals blank over 14​
grigory [225]

Answer:

x = 7

Step-by-step explanation:

simplify 16/32

16/32 divided by 8/8=2/4

2/4 divided by 2=1/2

so

1/2 = x/14

to get to 14  from 2 you need to multiply by 7

1/2 times 2/2 = 7/14

so x = 7

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4 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
1. what is the phythaforean theorem?
irina1246 [14]

Answer:

phythaforean theorem:

1 . The square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.

2.  Find the square root to find the accurate length of the hypotenuse.

distance formula:

1. The distance formula is used to determine the distance, d, between two points.

distance = speed × time

Formula- d= √x2-x1)²+(y2-y1)²

2. It's used for :

-Finding the perimeter of polygons

-Finding the area of rectangles

-Finding the equation of a circle

8 0
3 years ago
Plz help me with this
Ber [7]
I don't know what the expanded form is but the word form is two million nine hundred forty seven.
4 0
3 years ago
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