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3 years ago

Wht is the answer to this answer. what is a kilogram and milgram's

Mathematics

2 answers:

LiRa [457]3 years ago

5 0

Answer:

a kilogram = 1000 grams

milgram = 0,001 grams

Dennis_Churaev [7]3 years ago

3 0

Answer:

um its Review the size of grams and kilograms and how to convert between the two. Then, try some practice problems.

Step-by-step explanation:

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What percent of 1/4 is 2/3 and what percent of 1/6 is 2/3 ?

vlada-n [284]

Answer:

The percentages are 267% and 400% respectively.

Step-by-step explanation:

To find the answers of these, you need to divide the second number by the first. This will give you the percentage.

2/3 ÷ 1/4 = 8/3 = 2.67 = 267%

You can do the same for the second one.

2/3 ÷ 1/6 = 12/3 = 4 = 400%

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A 12 1/4 inch board is cut from a 34 3/4 inch board. The saw cut takes 3/8 inch. How much of the 34 3/4 inch board is left after

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Answer:

22 1/8

Step-by-step explanation:

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Answer:

Triangle ABCABCA, B, C the option C is correct.

Step-by-step explanation:

As in the triangle ABCABCA, B, C

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3 years ago

What is the value of 5 5 units, as a fraction greater than 1 1?

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3 years ago

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A center for medical services reported that there were 295,000 appeals for hospitalization and other services. For this group, 4

pshichka [43]

Answer:

a) 0.0025 = 0.25% probability that none of the appeals will be successful.

b) 0.0207 = 2.07% probability that exactly one of the appeals will be successful.

c) 0.9768 = 97.68% probability that at least two of the appeals will be successful

Step-by-step explanation:

For each appeal, there are only two possible outcomes. Either it is succesful, or it is not. The probability of an appeal being succesful is independent of other appeals, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

45% of first-round appeals were successful.

This means that $p = 0.45$

Suppose 10 first-round appeals have just been received by a Medicare appeals office.

This means that $n = 10$

(a) Compute the probability that none of the appeals will be successful.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.45)^{0}.(0.55)^{10} = 0.0025$

0.0025 = 0.25% probability that none of the appeals will be successful.

(b) Compute the probability that exactly one of the appeals will be successful.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.45)^{1}.(0.55)^{9} = 0.0207$

0.0207 = 2.07% probability that exactly one of the appeals will be successful.

(c) What is the probability that at least two of the appeals will be successful

This is $P(X \geq 2)$

Either less than two appeals are succesful, or at least two are. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0025 + 0.0207 = 0.0232$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0232 = 0.9768$

0.9768 = 97.68% probability that at least two of the appeals will be successful

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3 years ago