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MAVERICK [17]
3 years ago
7

Wht is the answer to this answer. what is a kilogram and milgram's

Mathematics
2 answers:
LiRa [457]3 years ago
5 0

Answer:

a kilogram = 1000 grams

milgram = 0,001 grams

Dennis_Churaev [7]3 years ago
3 0

Answer:

um its Review the size of grams and kilograms and how to convert between the two.  Then, try some practice problems.

Step-by-step explanation:

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Write an equation in standard form of the line that contains the point (-1,2) amd is perpendicular to y = 3x - 1
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Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is -\frac{1}{3} x

So now we have, 
y=- \frac{1}{3} x+b

To find b, we use the point that the line passes through and substitute it to the y and x values.

2=- \frac{1}{3} (-1)+b

which would give us b=5/3

Therefore, the equation of the line is 
y=- \frac{1}{3} x+ \frac{5}{3}
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3 years ago
Polygon B is a scaled copy of Polygon A using a scale factor of 5.
SVEN [57.7K]

Answer:

5times largerof apolygon

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T-shirts and More Print Shop will print any image on a mouse pad for a cost of $2 per mouse pad and a one-time charge of $12 to
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275 mouse pads were printed

Step-by-step explanation:

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4 0
2 years ago
If h(x) = 6 – x, what is the value of (h circle h) (10)?<br> –4<br> –2<br> 10<br> 16
Ganezh [65]

Answer:

10

Step-by-step explanation:

Here, we want to find the value of ;

h circle h(10)

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we have this as;

6-(6-x)

= 6-6 + x = x

Now, replace the x by 10; so we have h circle h(10)

5 0
3 years ago
Read 2 more answers
The rectangular coordinates of a point are given. Find the polar coordinates ​(r,theta​) of this point with theta expressed in r
alexandr402 [8]

Answer:}

In polar coordinates P is

P  ( 12 ; 2.618 )  

Step-by-step explanation:

The point (ectangular coordinates)  

P ( -6√3  ;   6 )       P  (  x ; y )

Polar coordinates   P ( r  ;  θ )

x = r cos θ

y = r sin θ                  r > 0    and     0  ≤ θ ≤ 2π

Then

r  =  √ (x)² + (y)²        r  =  √(36)²*3 +( 36)²       r = √144

r  =  12   (hypothenuse module always positive)

The point   P  ( -6√3  ;   6 )   is in second cuadrant  between 90° and 180°

angle between  r  and horizontal axis x  is equal to θ

tan α =  l.opp/ l.adj.    tan θ =  y/x       tan θ = - 6 /6√3

tan α = - 1/√3

Then α  =  180⁰ - 150⁰  = 30⁰  or     θ =  150⁰

to express that value in radians we have :

1 π radian      =   180⁰         ⇒   3,1416   radians  =  180⁰

                                                      x ??                  =   150⁰

x =  radians

Finally the point is   P  ( 12 ; 2.618 )  

6 0
3 years ago
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