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MAXImum [283]
3 years ago
13

The perimeter of a rectangle,p, is given by p =2L + 2W , where L is its length and w is its width what is the perimeter of a rec

tangle of length 15ft and width 15ft ?
Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:girl use google

Step-by-step explanation:what

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Find the GFC of 56 and 84. A factor tree for 84 is given below. The GCF of 84 and 56 is 7142128 .
guajiro [1.7K]

Answer:

28 is the GCF

Step-by-step explanation:

What I know about GCF is that it's a greatest (G) common (C) factor (F). The GCF of 84 and 56 is 7142128; false.

56- 56, 28, 14, 8, 7, 4, 2, 1.

84- 84, 42, 28, 21, 14, 12, 7, 6, 4, 3, 2, 1.

Hope this helps. :)

8 0
3 years ago
Read 2 more answers
Does anybody know how to do this please help meee
Mariulka [41]

Answer:

A

Step-by-step explanation: I believe it's A because It's the opposite but I'm not 100% certain, because I don't remember inverse statements.

6 0
2 years ago
What are coordinates the of y=1.25x-3
faust18 [17]
I hope this helps you

6 0
3 years ago
Select the problems which show the correct answers. (1.12 x 105) (6.06 x 105) Answer: 6.79 x 1010 (2 x 101)(3.0 x 101) Answer: 6
Arisa [49]
Since multiplication is commutative, we can rearrange the problem: 
(1.12*10^5)(6.06*10^5) = (1.12*6.06)(10^5*10^5)
Using the properties of exponents, we have:
(1.12*6.06)(10^10)
\\=6.7872*10^10

Again, multiplication is commutative, so we rearrange the problem; then we use the product property of exponents:
(2*10^1)(3*10^1)
\\=(2*3)(10^1*10^1)
\\=6*10^2

(2.775*10^-^4)(4.775*10^4)
\\=(2.775*4.775)(10^-^4*10^4)
\\=(2.775*4.775)(10^0)
\\=(2.775*4.775)(1)
\\=2.775*4.775=13.250625=1.3250625*10^1

5(8.14*10^2)=(5*8.14)(10^2)=40.7*10^2=4.07*10^3
6 0
3 years ago
Read 2 more answers
In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi
Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n  = 50

sample mean \overline x = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

X \sim N ( \mu \sigma)

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})

P(X>140) = 1 - P( Z\leq0.42)

From z tables,

P(X>140) = 1 - 0.6628

P(X>140) = 0.3372

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

Y \sim Binomial (np)

Y \sim Binomial (50,0.3372)

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49}  + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +...  + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}

P(Y ≥ 15) = 0.763

7 0
3 years ago
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