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3 years ago

X/-2+17=12 please help me with this equation

Mathematics

2 answers:

Triss [41]3 years ago

6 0

Answer:

x/-2=-5

-x=-10

x=10

.. ..

nevsk [136]3 years ago

4 0

Answer:

x=-10

Step-by-step explanation:

x/-2+17=12

x/-2=12-17

x/-2=-5

x=-5*2

x=-10

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If f(x) = 3x^2 – x + 3, then what is the remainder when f(x) is divided by x + 7?

Anton [14]

Answer:

the remainder is -52

Step-by-step explanation:

3x²-x + 3

x+7÷ 3x² - x +3

the remainder is -52

5 0

3 years ago

Whoever answers first ill mark brainlist

aivan3 [116]

Answer:

∠S = 19°

Step-by-step explanation:

Since all angles in a triangle add up to 180°, we must first find how much is left.

180 - 142 = 38

And since we know that the two lines are congruent, we know that the two other angles will be the same. So we divide the remaining by 2

38 ÷ 2 = 19

So both other angles are 19° meaning that ∠S is 19°

Hope this was helpful!

8 0

2 years ago

Read 2 more answers

A circle has a circumference of 266.9 inches. What is the Diameter of this circle? What is the Radius? Use 3.14 as the approxima

Natali5045456 [20]

Answer:

r= 42.48 and d=84.96

Step-by-step explanation:

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4 0

3 years ago

Write an equation of the line that passes through the given points. (-1,7) and (4, -8)

djverab [1.8K]

Answer:

y=-3x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-(-1))

m=-15/(4+1)

m=-15/5

m=-3

y-y1=m(x-x1)

y-7=-3(x-(-1))

y-7=-3(x+1)

y=-3x-3+7

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3 0

3 years ago

Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)

lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

Distance = $\sqrt{(-6)^2+3^2}$

Distance = $\sqrt{36+9}$

Distance = $\sqrt{45}\approx6.7082$

$6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}$

8 0

3 years ago