3 years ago

Solve using the quadratic formula: 2x^2=8x-7. There are four parts to this question labeled A-D.

Mathematics

1 answer:

Tasya [4]3 years ago

4 0

3x=2+4x I think I don’t know

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6 Which equation has a solution of s = 9.5 ? F -5s = -47.5 G -3 + s = 12.5 H --2s 19 J –1 + s = 10.5

earnstyle [38]

Answer:

F. -5s = -47.5

Step-by-step explanation:

F. -5s = -47.5

s = -47.5 / -5

s = 9.5

This is the correct option

G. -3 + s = 12.5

s = 12.5 + 3

s = 15.5 (Incorrect option)

J. –1 + s = 10.5

s = 10.5 + 1

s = 11.5 (Incorrect option)

5 0

3 years ago

Bob bought a bike for $250 and repaired it . He can now sell the bike for $300. What is the percent increase in the value bike ?

alexgriva [62]

Answer:20%

Step-by-step explanation:

250*20%=50

50+250=300

7 0

3 years ago

Perform the Indicated Operation. (-18)-(4)

Tems11 [23]

-22 is your answer because all you have to do is take 4 away from -18 and you get -22

7 0

4 years ago

Read 2 more answers

What is the size of the matrix resulting from

kogti [31]

Answer:

1×3 or 3×3 I think...........

7 0

3 years ago

Read 2 more answers

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

4 years ago