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Svetlanka [38]
2 years ago
12

Which is the best information to determine an athlete's abilities and needed areas of improvement?

Computers and Technology
2 answers:
katen-ka-za [31]2 years ago
7 0

Answer:

4

Explanation:

natka813 [3]2 years ago
3 0
It would be 2 because it would be the most accurate. In different games you get different experiences and say it’s a bad game for you the next game is how you play normal will show.
Hope this helps! Mark brainlist please!
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it just said i was blocked from brainly for a sec i was like- dang- then i logged in again then it was back to normal uHhHh can
PSYCHO15rus [73]

Answer:

it has been doing the same to me if your on a school computer at home then it will bug sometimes but if you were at school then it would probably be entirely blocked but idrk

Explanation:

5 0
3 years ago
Read 2 more answers
Write a Java class with the following methods: getArray(int numStrings) is an instance method that takes command line input (use
mezya [45]

Answer:

Follows are the code to this question:

import java.util.*;//import packae for user-input  

public class Main//defining a class Main

{

public String[] getArray(int numString)//defining a method getArray

{

String[] name=new String[numString];//defining array of String values

Scanner in = new Scanner(System.in);// creating scanner class object for input values from user-end

for(int i=0;i<numString;i++)//defining for loop for input multiple values

{

System.out.print("Enter String Value :");//print message

name[i]=in.nextLine();//input values

}

return name;//return array values

}

public String getLongestString(String[] sArray)//defining a method getLongestString

{

int m=0,mi=0; //defining integer variables

for(int i=0;i<sArray.length;i++)//defining for loop for check the longest value in array

{

if(m<sArray[i].length())//defining if block that checks m varaible value greater then sArray length  

{

m=sArray[i].length();//use m to hold sArray length

mi=i;//use max_index to hold i that is loop value

}

}

return sArray[mi];//return Longest value

}

public static void main(String[] args)//defining main method

{

Main s=new Main();//Creating object of main class    

String[] n;//defining string variable n  

n=s.getArray(5);//use n varaible to call getArray method and store its value

System.out.println("Longest value is: "+s.getLongestString(n));//use print method to call getLongestString method

}

}

Output:

please find attached file.

Explanation:

In the given java program code, inside the main class two method that is "getArray and getLongestString", is defined, in which the "getArray" method uses an integer variable in its parameter and inside the method, an array is defined that use a  scanner class for input array value.

  • In the "getLongestString" pass as a parameter and inside the method, two integer variable "m and mi" is defined that use in the loop to return the longest string value.
  • In the class main method is to define that creates a class object and call the above method and use the print method to return its value.  

4 0
3 years ago
Hi weegy, what is the latest android os?
KatRina [158]
<span>The newest android os is:
Android 7.0 Nougat

</span>
7 0
3 years ago
Andy wants to install a new Internet connection. He wants to take the fastest he can get. What are the maximum speeds for the fo
aksik [14]

Answer:

1. so if i wanted to build a linux server for web services(apache) with 1cpu and 2 gb of memory.-operating at 75% of memory capacity2. a windows server with 2 cpu/ 4gb memory- operating at 85% of memory capacity3. a storage server with 1 cpu/ 2gb memory- operating at 85% of memory capacityhow much memory do i have to add for each server. so that the utilization rate for both cpu and memory is at a baseline of 60%."the details for the cpu like its processor or the memory's speed isnt to be concerned" yeah i kept asking my teacher if he's even sure about the but the whole class seems to be confused and the project is due in 3 days..this is a virtualization project where i have to virtualize a typical server into an exsi hypervisor.

5 0
3 years ago
Which one of the following terms is defined as the material and surfaces upon which an artist works?1. Applied arts2. Context3.
babunello [35]

Answer:

The correct answer to the following question will be Option D (Media).

Explanation:

Media are the contact channels or devices used to store information or data and distribute it. The phrase refers to elements of the media marketing industry such as printed media, printing, mainstream media, film, theater, television and radio broadcast, and advertisement.

There are mainly three types of media, which are as follows:

  • Print media
  • Broadcast media
  • Internet

Using these three media, we can describe the content and the surfaces on which an artist works.

Therefore, Option D is the right answer.

5 0
3 years ago
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