Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
Step 1: Simplify both sides of the equation.
8−2(3−x)=4x+6
8+(−2)(3)+(−2)(−x)=4x+6(Distribute)
8+−6+2x=4x+6
(2x)+(8+−6)=4x+6(Combine Like Terms)
2x+2=4x+6
2x+2=4x+6
Step 2: Subtract 4x from both sides.
2x+2−4x=4x+6−4x
−2x+2=6
Step 3: Subtract 2 from both sides.
−2x+2−2=6−2
−2x=4
Step 4: Divide both sides by -2.
−2x
−2
=
4
−2
Step-by-step explanation:
FALSE
metric system is known as the SI or sytem international system
it is used everywhere except for those few who cling to the english system (USA and UK)
