So he started at
9:30 a.m.
three hours and ten minutes later
9+3 is 12
30 + 10 is 40
12:40 p.m.
it took him 47 minutes to replace
so 12:40 plus 47 minutes is
1:27 p.m.
He then rode for another 56 minutes to finish the race
so 1:27 plus 56 minutes
2:23 p.m.
Hope this helps :)
Answer:
Step-by-step explanation:
You can't solve for the values of a and b because 6a³b²·2a⁴b³ is an expression, not an equation. However, you can simplify the expression:
6a³b²·2a⁴b³ = 6·2·a³⁺⁴b²⁺³ = 12a⁷b⁵
Sorry don’t now the answer to this problem
Answer:
they are both variables so yes
Probably true
you can test it too