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3 years ago

Mark wants to round to the nearest hundred to estimate the sum of 271 and 582.

Mathematics

1 answer:

DIA [1.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

Part A:

Mark did not round to the nearest hundreds, he rounded to the nearest tens.

Option A (Incorrect):

271 and 582 are normally not rounded down, unless we are using limits coming from the left and a unique equation.

Option B (Incorrect):

271 as the same problem as option A, but 582 rounding to 600 is correct. It doesn't make sense to round both numbers differently, unless stated.

Option C (Incorrect):

271 rounding to 300 is correct, but 582 is not normally rounded down to 500 unless we are using limits coming from the left and a unique equation. Unless stated, don't round both numbers differently.

Option D (Correct):

271 rounded to 300 and 582 rounded to 600 looks correct for rounding to the hundreds.

Part B:

There are two ways to solve this question:

One way:

271 + 582 = 853

Round 853 to the nearest hundred for 900

(Note: Round 853 to the nearest tens for 850.)

Second way:

271 + 582

Round Numbers:

300 + 600

= 900

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See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

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12x^2 - 3y^2 - 108 = 0

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<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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The transverse axis is calculated as:

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Evaluate the quotient

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<u>The vertices</u>

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The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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a = 3 and b = 6

The co-vertices are

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See attachment for the graph of the hyperbola