2. Find F(x)+g(x)<br> 4 options to pick from

USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacture

anygoal [31]

Answer: No, It does not indicates that the population proportion of consumers loyal to Chevrolet is more than 47%.

Step-by-step explanation:

Let p denotes the proportion of consumers loyal to Chevrolet.

As per given , we have

$H_0: p=0.47\\\\ H_a: p>0.47$

Since the alternative hypothesis $(H_a)$ is right-tailed so the test would be a right-tailed test.

Also , it is given that ,Chevrolet did a study of a random sample of 1006 Chevrolet owners and found that 490 said they would buy another Chevrolet.

i.e. n = 1006

x= 490

$\hat{p}=\dfrac{490}{1006}=0.487$

Test statistic :

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

, where p=population proportion.

$\hat{p}$ = sample proportion

n= sample size.

i.e. $z=\dfrac{0.487-0.47}{\sqrt{\dfrac{0.47(1-0.47)}{1006}}}=1.08$

P-value (for right-tailed test)= P(z>1.08)=1-P(z≤1.08) [∵P(Z>z)=1-P(Z≤z)]

=1- 0.8599=0.1401 [By z-value table.]

Decision : Since p-value (0.14) is greater than the significance level ( $\alpha=0.01$ ) , it means we are failed to reject the null hypothesis.

Conclusion : We have sufficient evidence to support the claim that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice.

Hence, it does not indicates that the population proportion of consumers loyal to Chevrolet is more than 47%.

7 0

4 years ago

The faces of a tetrahedron die are numbered 1 to 4. if each of the 4 sides is equally likely to land down, what is the probabili

Hoochie [10]

The probability distribution for the face landing down = 4/15

<h3>What is the probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information:</h3>

If we assign 1 probability x

then 2 has probability 1/2 x.

Similarly,

then 3 has probability = 1/2((1/2)*x) = (1/4)*x

so

then 4 has probability = 1/2((1/4)*x) = (1/8)*x

These probabilities need to sum to 1.

Hence:

$x+\frac{1}{2} x+\frac{1}{4} x+\frac{1}{8} x=1$

or equivalently

(15/8)*x = 1

x = 8/15

the probability distribution for the face landing down = (1/2)*(8/15)

= 8/30

= 4/15

To know more about probability visit:

brainly.com/question/1581057

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I understand that the question you are looking for is:

A tetrahedral die has four faces, numbered 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice as likely as 3, and so on) what is the probability distribution for the face landing down?

7 0

2 years ago

93748 x 837482768836334

AlexFokin [52]

42 to the power of 100

3 0

3 years ago

Read 2 more answers

512 64 18 16] 4 2 2 2 8 1 42 111 ( 8.1.2.1.1 4,2121 81111

vagabundo [1.1K]

Do you have an actual question you need help with or what

4 0

3 years ago

A new roller coaster at an amusement park requires individuals to be at least 4' 8" (56 inches) tall to ride. It is estimated

Maksim231197 [3]

Answer:

a) 34.46% of 10-year-old boys is tall enough to ride this coaster.

b) 78.81% of 10-year-old boys is tall enough to ride this coaster

c) 44.35% of 10-year-old boys is tall enough to ride the coaster in part b but not tall enough to ride the coaster in part a

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 54, \sigma = 5$

a. What proportion of 10-year-old boys is tall enough to ride the coaster?

This is 1 subtracted by the pvalue of Z when X = 56.

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{56 - 54}{5}$

$Z = 0.4$

$Z = 0.4$ has a pvalue of 0.6554

1 - 0.6554 = 0.3446

34.46% of 10-year-old boys is tall enough to ride this coaster.

b. A smaller coaster has a height requirement of 50 inches to ride. What proportion of 10-year-old boys is tall enough to ride this coaster?

This is 1 subtracted by the pvalue of Z when X = 50.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 54}{5}$

$Z = -0.8$

$Z = -0.8$ has a pvalue of 0.2119

1 - 0.2119 = 0.7881

78.81% of 10-year-old boys is tall enough to ride this coaster.

c. What proportion of 10-year-old boys is tall enough to ride the coaster in part b but not tall enough to ride the coaster in part a?

Between 50 and 56 inches, which is the pvalue of Z when X = 56 subtracted by the pvalue of Z when X = 50.

From a), when X = 56, Z has a pvalue of 0.6554

From b), when X = 50, Z has a pvalue of 0.2119

0.6554 - 0.2119 = 0.4435

44.35% of 10-year-old boys is tall enough to ride the coaster in part b but not tall enough to ride the coaster in part a

5 0

3 years ago

2. Find F(x)+g(x) 4 options to pick from