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VladimirAG [237]
3 years ago
8

-190*(x)483-913+342-4569-(y)94=

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

-91770x - 94y - 5140

Step-by-step explanation:

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x=11.9 mm

Step-by-step explanation:

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She will win because she's black lol

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Round 3004 to 3 significant digits
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If an angle measures 18° what is the measure of its complement​
Lisa [10]

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer.....

<h3>Complement Angle = 90° </h3>

<em>= 90 - 18</em>

<em>= 72</em>

<em>--</em><em>></em><em> </em><em>7</em><em>2</em><em>°</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>complement</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>1</em><em>8</em><em>°</em>

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5 0
3 years ago
A professor believes the class he is teaching in the current semester is above the average of the classes he has taught. In orde
MakcuM [25]

Answer:

1) Since we know the info from all the students that he teaches and we know the population deviation from past data we can use a z test to check the hypothesis

2) t=\frac{82-78}{\frac{15}{\sqrt{120}}}=2.921    

3) p_v =P(Z>2.921)=0.0017  

Since the p value is lower than the significance level of 0.01 we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis

4) For this case since we reject the null hypothesis we have enough evidence ot conclude that the scores for this semester are above the historical value of 78 so then the claim stated by the teacher makes sense

Step-by-step explanation:

Part 1

Since we know the info from all the students that he teaches and we know the population deviation from past data we can use a z test to check the hypothesis

Part 2

\bar X=82 represent the sample mean  for the scores

\sigma=15 represent the population standard deviation

n=120 represent the sample selected

\alpha=0.01 significance level  

System of hypothesis

He wants to test if the group for this current semester is above the average of the classes he has taught (mean 78), the system of hypothesis are:

Null hypothesis:\mu \leq 78  

Alternative hypothesis:\mu > 78  

Since we know the population deviation we can use the following statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{82-78}{\frac{15}{\sqrt{120}}}=2.921    

Part 3

We can calculate the p value for this test with this probability taking in count the alternative hypothesis:

p_v =P(Z>2.921)=0.0017  

Since the p value is lower than the significance level of 0.01 we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis

Part 4

For this case since we reject the null hypothesis we have enough evidence ot conclude that the scores for this semester are above the historical value of 78 so then the claim stated by the teacher makes sense

5 0
4 years ago
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