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olasank [31]
3 years ago
9

Which set of ordered pairs does not represent a function?

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

2nd one

Step-by-step explanation:

The 2nd one has two ordered pairs that have the same x value.

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anygoal [31]

Answer:

adaasdaa

Step-by-step explanation:

6 0
3 years ago
PLS HELP!!! due to inflation nominal prices are usually there were to demand increases. After the second increase the price for
SashulF [63]

Answer:

The first increase was of 60%.

Step-by-step explanation:

The initial value of the product is x.

The first increase was of y.

The second increase is of 25%, that is, 1.25.

The final price was double the original, so 2x.

This situation can be modeled by the following equation:

xy(1.25) = 2x

We want to find y.

Simplifying by x

1.25y = 2

y = \frac{2}{1.25}

y = 1.6

After the first increase, the value was 1.6 of the original value, that is a increase as a percent of (1.6 - 1)*100 = 60%.

8 0
3 years ago
Solve multi-step equations with various solution sets (7th grade):<br><br> 6x + 4 = 2(3x - 5)
Lerok [7]

Answer:

X =0

Step-by-step explanation:

6x + 4 = 6x-10

6x - 6x = -10 - 4

0 ≠ -14

3 0
3 years ago
Perform the indicated operation and write the result in the form a+bi:<br><br> (4/7 - i)(8/7 + 7/5i)
aivan3 [116]

We will apply the "FOIL" method for multiplying two binomials. In this method you will:

  1. Multiply the First terms of each binomial
  2. Multiply the Outside terms of each binomial
  3. Multiply the Inside terms of each binomial
  4. Multiply the Last terms of each binomial
  5. Add all of the new terms you have just found together

The mathematical representation of the FOIL method is shown as:

(a + b)(c + d) = ac + ad + bc + bd


Let's apply the FOIL method.

  1. The first two terms of each binomial are \frac{4}{7} and \frac{8}{7}. Multiplied together, we find the new term of \frac{4}{7} \cdot \frac{8}{7} = \frac{4 \cdot 8}{7 \cdot 7} = \frac{32}{49}.
  2. The outside two terms are \frac{4}{7} and \frac{7}{5} i. Multiplied together, these two terms are \frac{4}{7} \cdot \frac{7}{5}i = \frac{4 \cdot 7}{7 \cdot 5}i = \frac{28}{35}i.
  3. The inside two terms are -i and \frac{8}{7}. Multiplied together, these two terms are - \frac{8}{7} i.
  4. The last two terms are -i and \frac{7}{5} i. Multiplied together, these two terms are -i \cdot \frac{7}{5}i = -\frac{7}{5} i^2. Remember though that i^2 = 1, so our new term is actually \frac{7}{5}.
  5. Added together, we get: \frac{32}{49} + \frac{28}{35} i - \frac{8}{7} i + \frac{7}{5} = \frac{160}{245} + \frac{196}{245}i - \frac{280}{245}i + \frac{343}{245} = \frac{503}{245} - \frac{84}{245} i = \frac{503}{245} - \frac{12}{35}i.

Our final answer is \boxed{\frac{503}{245} - \frac{12}{35}i}.

7 0
3 years ago
Jake cuts out five-pointed stars. They are different sizes, but they all have the same shape. The side lengths within each star
avanturin [10]
60 I think I am not 100%
6 0
3 years ago
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