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Furkat [3]
3 years ago
12

Pls help me with this math

Mathematics
2 answers:
malfutka [58]3 years ago
8 0

Answer: Here the answer

Step-by-step explanation:

Question 1: B

Question 2: C

Basile [38]3 years ago
8 0

Answer:

Picture 1 is B and picture 2 is C

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Y = a( x-h)^2 + k
prohojiy [21]
Can you summarize this?
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3 years ago
Please help with exercise 7
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A. 10p
b. 10p-75
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3 0
4 years ago
Find the surface area
Korvikt [17]

Answer:

A≈9248.85

Step-by-step explanation:

A=2πrh+2πr2=2·π·32·14+2·π·322≈9248.84877

4 0
2 years ago
a table was sold at 20%loss but had it sold for RS 160 more these would have been a profit 20%. find cp​
jekas [21]

Answer:

Rs 400

Step-by-step explanation:

Let us assume that the cost price of the article = x

Selling price = S.P

Cost price = C.P

Loss = %Loss × C.P(percentage loss × Cost Price)

S.P = C.P - Loss

In the question, Loss = 20%

S.P = x - 20x/100

Find the Lowest Common Multiple

S.P= 100x - 20x/100

S.P = 80x/100.........Equation 1

In the question, we are told if the article was sold for RS 160 more, it would have made a profit of 20%

Profit = %profit × C.P(percentage profit × Cost Price)

S.P = C.P + Profit

In the question, profit = 20%

S.P = x + 20x/100

Find the Lowest Common Multiple

S.P= 100x + 20x/100

S.P = 120x/100.........Equation 2

Hence,

Equation 2 - Equation 1 = Rs 160

= 120x/100 - 80x/100 = 160

= 40x/100 = 160

Cross multiply

40x = 100 × 160

40x = 16000

x = 16000/40

x = Rs 400

Since x = Cost price, the cost price of the table = Rs 400

4 0
3 years ago
What initial investment must be made to accumulate $60000 in 17 years if the money is invested in a mutual fund that pays 12% an
mars1129 [50]

$7881.18

Step-by-step explanation:

   Let the initial Investment be P_{0}. The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.

   As the annual interest rate is 12%, the monthly interest rate is 1%.

Since this is a compound interest problem, the total amount can be modeled as follows: P(t)=P_{0}(1+\frac{i}{100})^{t}

Here i is the interest rate, i.e 1, and t is the number of time periods, i.e 17\textrm{ years x }12\frac{\textrm{months}}{\textrm{year}}= 204\textrm{ months}

60,000=P_{0}\textrm{ x }(\frac{101}{100})^{204}

P_{0}=7881.18

∴ Initial Investment = $7881.18

4 0
3 years ago
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