5. What is the balance in an account opened with $25,000 earning 6% interest compounded yearly

Find the equation of the line through point (5,1) and perpendicular to 5x−y=−3.

Elanso [62]

Answer:

you will need to specify a scale and draw the line from which I will solve with simultaneous linear equations

3 0

3 years ago

Read 2 more answers

Avocado farmers use the percent of dry matter, the matter left after dehydration, from sample avocados in their orchards to dete

ELEN [110]

That would be (1.8 / 10) * 100

= 0.18 * 100

= 18% answer

5 0

3 years ago

Read 2 more answers

Mr. Nielsen invested $250,000 in two different automobile companies. The first earned a 5% profit, and the second earned a 10% p

dem82 [27]

Answer: $100,000

Step-by-step explanation:

Let P be the amount he invested in 5% profit .

then 250,000-P be the amount he invested in 10% profit .

The total profit he earns at 5% =5% of P

⇒The total profit he earns at 5 %=0.05P

Now, The total profit he earns at 10% =10% of (250,000-P)

⇒The total profit he earns at 10%= $0.1(250,000-P)=25,000-0.1P$

According to the question,

$3(0.05P)=25,000-0.1P\\\Rightarrow\ 0.15P=25,000-0.1P\\\Rightarrow\ 0.25P=25,000\\\Rightarrow\ P=\frac{25000}{0.25}\\\Rightarrow\ P=100,000$

Thus, the money he invest in the company that made 5%= $100,000

4 0

4 years ago

Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use

evablogger [386]

Answer:

(1) Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let $\mu_1$ = mean annual family income for 12 people making inquiries at the first development

$\mu_2$ = mean annual family income for 24 people making inquiries at the second development

$s_1$ = standard deviation of annual family income for 12 people making inquiries at the first development

$s_2$ = standard deviation of annual family income for 24 people making inquiries at the second development

$n_1$ = sample of people of first development i.e. 12

$n_2$ = sample of people of second development i.e. 24

(1) Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$ {population means are same}

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$ {population means are different}

<u>DECISION RULE ;</u>

If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, $H_0$ .
If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, $H_0$ .

(2) The test statistics is given by;

$\frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1+n_2-2$

where, $X_1bar$ = Sample mean income of people at first development

= $153,000

$X_2bar$ = Sample mean income of people at second development = $171,000

$s_1$ = $42,000 and $s_2$ = $30,000

$s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2}}$ = $\sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2} }{12+24-2}}$ = 34344.30

Test statistics = $\frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24} } }$ ~ $t_3_4$

= -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

4 0

4 years ago

Ill mark brainliest thanks

Trava [24]

Answer:

first one

Step-by-step explanation:

4 0

3 years ago