Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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12 ft I had the question the other day on online school :)
13 + (-12) - (-5)
13 - 12 + 5
1 + 5
= 6.
Answer is A)
<span>Last
year, Shantell bought a car for 24 000 dollars. It decreases to 21 000 dollars
this current year.
Let’s find for the percentage that it decreased.
=> in 24 000 the 50% is 12 000 as we all know since it’s divided by 2. So
meaning, the possible answer is less than 50%.
=> now 25% of 24 000 is 6 000, and the amount that we’re looking is 3000,
thus, the answer is 12.5%
=> 24 000 * 0.125 = 3000
=> 24 000 – 3000 = 21 000</span>
