2 years ago

5(t+4) please heelllpppp

Mathematics

2 answers:

natta225 [31]2 years ago

6 0

Answer:

5t+20

Step-by-step explanation:

ArbitrLikvidat [17]2 years ago

6 0

Answer:

5t+20

Step-by-step explanation:

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3 ft Find the outer perimeter of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate it. 4 ft 5 ft

Sedbober [7]

Answer:

perimeter = 19.42 ft

Step-by-step explanation:

perimeter of semi circle = 6π/2 = 9.42

perimeter of cone = 5 + 5 = 10

10 + 9.42 = 19.42 ft

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2 years ago

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5x+8=3x-6 plz help me asap

Ray Of Light [21]

Answer:

x = -7

Step-by-step explanation:

5x+8=3x-6

Subtract 3x from each side

5x-3x+8=3x-3x-6

2x+8 = -6

Subtract 8 from each side

2x+8-8 = -6-8

2x = -14

Divide by 2

2x/2 = -14/2

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3 years ago

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-7/3x + 2/3 = -18<br> What is the solution?

xxMikexx [17]

Answer:

Step-by-step explanation:

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2 years ago

Prove: An odd number squared is an odd number. = (2n + 1)2

Mnenie [13.5K]

Answer:

${(2n + 1)}^{2} = 4 {n}^{2} + 4n + 1 = 2(2 {n}^{2} + 2n) + 1$

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2 years ago

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

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2 years ago