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3 years ago

Please help!! write a quadratic function f whose zeros are 6 and 3

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

$x^{2} - 9x +18$

Step-by-step explanation:

To solve the question work backwords. First, set an equation equal to 0 where the solutions are 6 and 3. For example, (x-6)(x-3)=0. Then, use FOIL to multiply it out. When it is multiplied you are left with the function $x^{2} - 9x +18$ .

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L is the midpoint of line segment KM. If KL = 2x - 3 and LM = x + 7. find the value of x.

tatyana61 [14]

Answer:

x = 10

Step-by-step explanation:

Since L is the midpoint

KL = LM

2x-3 = x+7

Subtract x from each side

2x-3-x = x+7-x

x-3 = 7

Add 3 to each side

x-3+3 = 7+3

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4 years ago

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ok you need formula for surface area.

SA = πrh+2πr^2

Plug in 25 and 5

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2 years ago

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3 years ago

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3 years ago

100 point to the first correct answer

miss Akunina [59]

Answer:

X ~ B(n, p)

Given: X ~ B(2, 5/17)

⇒ n = 2

⇒ p = 5/17

Binomial distribution formula:

$\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x$

As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):

$\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}$

$\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}$

$\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}$

**Probability Distribution Table attached**

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3 years ago