Answer:
B.
Step-by-step explanation:
The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.
∴ is the additional fact needed to prove
Hope this helps :)
Answer:
the surface area of the cube is :-
=》
Step-by-step explanation:
surface area of a cube =
=》
=》
=》
so, Surface area of the cube is <u>1014</u> square feet
Given:
No of users in February is 45,000 and in october its 60,000.
t=2
Therefore, approximate no of users after 2 years is 106667.
Answer:
Step-by-step explanation:
Hello!
a)
The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.
To calculate the mean for data organized in this type of table you have to use the following formula:
X[bar]= (∑x'fi)/n
Where
x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2
fi represents the observed frequency for each class
n is the total of observations, you can calculate it as ∑fi
<u>Class marks:</u>
x₁'= (120+124)/2= 122
x₂'= (124+128)/2= 126
x₃'= (128+132)/2= 130
x₄'= (132+136)/2= 134
x₅'= (136+140)/2= 138
Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.
n= 7 + 8 + 13 + 9 + 3= 40
X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3
The estimated average height is 129.3cm
b)
This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.
The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a mean value within the interval to calculate the mean of the sample.
I hope this helps!
6.39
It’s 2 places to the right of the decimal and since 6 is 5 or greater, you will round the 8 up