Ask question

Ask question

All categories

3 years ago

9

The store is selling lemons at 2 for $1.50. Each lemon yields about 2 tablespoons of juice. How much will it cost to buy enough

lemons to make a 10-inch lemon pie requiring 3⁄4 cup of lemon juice?

1 answer:

Andrei [34K]3 years ago

8 0

Answer:

$4.50

Step-by-step explanation:

3/4 cups = 12 tablespoons

$1.50 yields 4 tablespoons

12 / 4 = 3 purchases at $1.50 = $4.50

You might be interested in

A man invests a total of $9,493in two savings accounts. One account yields 9% simple interest and the other 10% simple interest.

Tju [1.3M]

$ 1850 was invested in 9% account

<u>Solution:</u>

Given that

Total amount invested by man in two saving accounts = $9493

Simple interest on one account =9%

Simple interest on second account = 10%

Total interest earned = $930.80

Need to determine amount invested in 9 % account.

Let assume amount invested in account where Simple Interest is 9% = x

And assume amount invested in account where Simple Interest is 10% = y

As total amount invested in two accounts is $9493

=> x + y = 9493

=> y = 9493 - x ------(1)

$\text { Simple Interest }=\frac{\text { Amount Invested } \times \text {rate of interest } \times \text {time}}{100}$

$\begin{array}{l}{\text { Simple interest when rate of interest is } 9 \%=\frac{x \times 9 \times 1}{100}=\frac{9 x}{100}} \\\\ {\text { Simple interest when rate of interest is } 10 \%=\frac{y \times 10 \times 1}{100}=\frac{10 y}{100}}\end{array}$

As total interest earned = $930.80

$\begin{array}{l}{\Rightarrow \frac{9 x}{100}+\frac{10 y}{100}=930.80} \\\\ {\Rightarrow 9 x+10 y=930.80 \times 100} \\\\ {\Rightarrow 9 x+10 y=93080}\end{array}$

On substituting value of y from equation(1) in above equation , we get

9x + 10 (9493 – x) = 93080

=> 9x + 94930 – 10x = 93080

=> -x = 93080 – 94930

=> -x = -1850

=> x = 1850

Amount invested in account where Simple Interest is 9% = x = $1850

Hence $1850 was invested in 9% account.

5 0

3 years ago

PLEASE ANSWERRR!!!!!!

Fantom [35]

Answer:

C

Step-by-step explanation:

A function cannot have multiple y values for one x value.

Option A lists the y values of -8 and 10 for the x value of -4. Therefore this is not a function.

Option B lists 0, 5, 10, AND 15 all for -1. This can't be a function either.

Option C does not have two of the same x values for different results. Although both 0 and 9 give you the answer of 1 for the y value, this is perfectly okay in a function. This is your answer.

8 0

3 years ago

$15,000 is invested for 15 years with an APR of 4.2% and monthly compounding.

Phoenix [80]

Answer:

51-54: Simple Interest. Calculate the amount of money you will have in the following accounts after 5 years, assuming that you eam simple interest 51. You deposit $ 700 in an account with an annual interest rate of 4% 52. You deposit $1200 in an account with an annual interest rate of 3% 53. You deposit $3200 in an account with an annual interest rate of 3.5% 54. You deposit $1800 in an account with an annual interest rate of 3.8% 55-56: Simple versus Compound Interest. Complete the following tables, which show the performance of two investments over a 5-year period. Round all figures to the nearest dollar. 55 Suzanne deposits $3000 in an account that earns simple interest at an annual rate of 2.5%. Derek deposits $3000 in an account that earns compound interest at an annual rate of 2.5%. Suzanne's Suzanne's Derek's Annual | Derek's Year Annual Interest Balance Interest Balance rest formula to the stated pe 57-62: Compound Interest. Use the compound interest form compute the balance in the following accounts after the state riod of time, assuming interest is compounded annually. 57. $10,000 is invested at an APR of 4% for 10 years. 58. $10,000 is invested at an APR of 2.5% for 20 years. 59. $15,000 is invested at an APR of 3.2% for 25 years. 60. $3000 is invested at an APR of 1.8% for 12 years. 61. 55000 is invested at an APR of 3.1% for 12 years. 62. $ 40,000 is invested at an APR of 2.8% for 30 years. 63-70: Compounding More Than Once a Year. Use the appropriate compound interest formula to compute the balance in the following accounts after the stated period of time. 63. $10,000 is invested for 10 years with an APR of 2% and quarterly compounding. 64. $2000 is invested for 5 years with an APR of 3% and daily compounding 65. $25,000 is invested for 5 years with an APR of 3% and daily compounding 66. $10,000 is invested for 5 years with an APR of 2.75% and monthly compounding. 67. $2000 is invested for 15 years with an APR of 5% and monthly compounding 68. $30,000 is invested for 15 years with an APR of 4.5% ana daily compounding. 69. $25,000 is invested for 30 years with an APR of 3.7% quarterly compounding. 70. $15,000 is invested for 15 years with an APR of 4.2% monthly compounding. 71-74. Annual.

Hope this helps

7 0

2 years ago

What polynomial identity should be used to prove that 35 = 8 + 27

Julli [10]

Answer:

Sum of cubes identity should be used to prove 35 =3+27

Step-by-step explanation:

Prove that : 35 = 8 +27

Polynomial identities are just equations that are true, but identities are particularly useful for showing the relationship between two apparently unrelated expressions.

Sum of the cubes identity:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

Take RHS

8+ 27

We can write 8 as $2 \times 2 \times 2 = 2^3$ and 27 as $3 \times 3 \times 3 = 3^3$ .

then;

8+27 = $2^3+3^3$

Now, use the sum of cubes identity;

here a =2 and b = 3

$2^3+3^3 = (2+3)(2^2-2\cdot 3+3^2)$

or

$2^3+3^3 = (5)(4-6+9)$ $= 5 \cdot 7 = 35$ = LHS proved!

therefore, the Sum of cubes polynomial identity should be used to prove that 35 = 8 +27

4 0

2 years ago

Read 2 more answers

Please help me I don’t understand this

IrinaVladis [17]

Answer:

perfect sq=4/25,9,36

perfect cube=8/125,1/27

both=1,64

6 0

2 years ago