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luda_lava [24]
3 years ago
5

What condition results in magma cooling and forming a “glassy” igneous rock?

Advanced Placement (AP)
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:C

Explanation:

Gennadij [26K]3 years ago
6 0

Answer: C)  extremely rapid cooling

Explanation:

When magma goes through extremely rapid cooling and especially if it did not dissolve enough water into it, it could freeze to glass or the mineral crystals that will be formed will be so small, they will look like glass.

This is because the reactions that occur to create minerals are affected directly by temperature such that if the magma cools down extremely slowly, it will form very large crystals but extremely fast would result in small crystals.

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2 years ago
What are the main differences between the House of Representatives and the Senate?
Reptile [31]

Answer:

the differance between the house of represenates is that the house has 100 and the senate has 435

Explanation:

3 0
3 years ago
Why do you think it was important for a knight to be pious ?
Goryan [66]
Because he represented his kingdom with how he acted
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3 years ago
Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th
lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2

Finding the boundaries of the function gives;

0\times e^{4-0^2} = 0 and 2\times e^{4-2^2} = 2

At t = 1, we have 1\times e^{4-1^2} = e^{3} = 20.086

We find the maximum point as follows;

\frac{\mathrm{d} \left (t\times e^{4-t^2}   \right )}{\mathrm{d} x}=0

From which we have;

\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0

e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0

e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\

e^{4-t^2}=0 or (1 - 2\times t^2 })=0

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for  0 ≤ t ≤ 0  1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0
3 years ago
What does the quote from Trotsky's Diary in Exile reveal about his and his like-minded comrades' point of view regarding the fat
Nostrana [21]

Answer: It revealed the other exact political landscape and sociocultural landmark of writer's philosophical line of thoughts. It opens a wide range of iconic point of views.

Explanation: It is a varying attempt to point out the anarchical systems

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