Answer :
<u>A the triangle is not a right </u><u>triangle</u>
<u>D </u><u>costheta</u><u> </u><u><0</u>
The law of cosines says:
a²=b²+c²−2bccos(θ)
Rewriting:
2bccos(θ)=b²+c²−a²<0
So cos(θ)<0cos(θ)<0 since 2bc>02bc>0. Since 0<θ<π0<θ<π in any triangle,
π/2<θ<π
So:
1. θ is not an acute angle.
2 The triangle is not a right triangle. In a right triangle, one of the angles is 90 degrees and the other two are then less than 90 degrees. This triangle has an angle greater than 90 degrees.
3. cos(θ)<0 is true.
4. cos(θ)>0 is false -3 says cos(θ) is negative; a number can't be both positive and negative.
neverminding the jumbled lingo, is simply asking for the equation of the tangent line at that point, it says all tangents, well, there's only one passing there.
we can simply get the derivative of f(x) and take it from there.
since now we know the slope when x = 3/2, then we can just plug that into its point-slope intercept form, along with the coordinates.
Only 3 because 3 times 3 = 9 and 3 times 4 = 12
