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umka2103 [35]
3 years ago
14

Can anyone help me with this problem?

Mathematics
1 answer:
sdas [7]3 years ago
3 0
First find slope
(Y2-y1)/(x2-x1)
(-3-(-1))/(-6-9) = -2/-15 = 2/15
Point slope: y-y1 = m(x-x1)
Solution: y + 1 = 2/15(x - 9)
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What are the solutions of the quadratic equation? 4x^2+9x-9=0
vagabundo [1.1K]

Answer:

x=3/4

x=-3

Step-by-step explanation:

we have

4x^2+9x-9=0

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^2+9x-9=0

so

a=4\\b=9\\c=-9

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(4)(-9)}} {2(4)}

x=\frac{-9(+/-)\sqrt{225}} {8}

x=\frac{-9(+/-)15} {8}

x=\frac{-9+15} {8}=3/4

x=\frac{-9-15} {8}=-3

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3 years ago
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Answer:

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Answer: 62.7 is rounded to the nearest hundredth.

Step-by-step explanation:

Because...

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Answer:

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