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3 years ago

Can anyone help me with this problem?

Mathematics

1 answer:

sdas [7]3 years ago

3 0

First find slope
(Y2-y1)/(x2-x1)
(-3-(-1))/(-6-9) = -2/-15 = 2/15
Point slope: y-y1 = m(x-x1)
Solution: y + 1 = 2/15(x - 9)

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The Quadrilateral is JKLM,

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Given any 2 point P(m,n) and Q(k,l),

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thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

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$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

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thus the distances connecting the opposite entrances can be calculated as follows:

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$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

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5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

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