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Artyom0805 [142]

3 years ago

7

The measure of the first angle in a triangle is 60 degrees, the second angle is 90 degrees. How many degrees is the measure of t

he third angle? Degrees.

2 answers:

Ludmilka [50]3 years ago

5 0

If it’s out of 180 degrees it’s 30 degrees

erastovalidia [21]3 years ago

4 0

The answer is 30 degrees. The angles in a triangle have to add up to 180 degrees, so add the ones that are given (90°+60°) which equals 150°, and subtract 180°-150°, and you get the measurement of the missing angle, which is 30°

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Solve ABC <br>c=10, B=35°, C=65%

NISA [10]

Answer:

Part 1) The measure of angle A is $A=80\°$

Part 2) The length side of a is equal to $a=10.9\ units$

Part 3) The length side of b is equal to $b=6.3\ units$

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

$A+B+C=180\°$

substitute the given values

$A+35\°+65\°=180\°$

$A+100\°=180\°$

$A=180\°-100\°=80\°$

step 2

Find the length of side a

Applying the law of sines

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}$

$a=\frac{10}{sin(65\°)}(sin(80\°))$

$a=10.9\ units$

step 3

Find the length of side b

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}$

$b=\frac{10}{sin(65\°)}(sin(35\°))$

$b=6.3\ units$

5 0

3 years ago

Suppose I invest $400 in an account that pays 3% interest annually. How much will I have in the account after 2 years, assuming

Simora [160]

I agree ☝ which the guy above me because I worked that out and was thinking about it and I got that answer

7 0

3 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

HELP ASAP PLEASE

dimaraw [331]

Answer:

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate

10%. The second car depreciates at an annual rate of 15%. What is the approximate difference in the ages of the two

cars?

Step-by-step explanation:

the answer is in the question

7 0

3 years ago

Insert parentheses on the left side of the equation to make the statement true for all values of p

lukranit [14]

7+5(p-p)=7
because 7+5p-5p=7
cross our the 5p because 5p-5p is 0
7=7
~JZ
Hope it helps!

3 0

3 years ago