Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).
2 answers:
Answer:
Y = -x + 2
Step-by-step explanation:
y = -x + 8
y = 1x + b
10 = 8 + b
b = 2
Answer:
y-y1=m(x-x1)
y-10=8(x-8)
y-10=8x-64
y-10+64-8x
y+54-8x
y-8x+54
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