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Gnoma [55]
3 years ago
15

Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

Y = -x + 2

Step-by-step explanation:

y = -x + 8

y = 1x + b

10 = 8 + b

b = 2

VladimirAG [237]3 years ago
5 0

Answer:

y-y1=m(x-x1)

y-10=8(x-8)

y-10=8x-64

y-10+64-8x

y+54-8x

y-8x+54

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<img src="https://tex.z-dn.net/?f=3x%20%5E%7B2%7D%20%2B%2010x%20%2B%208" id="TexFormula1" title="3x ^{2} + 10x + 8" alt="3x ^{2}
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