Select the correct answer.

Mathematics

2 answers:

Luda [366]3 years ago

7 0

Answer:

B) (X-3)

Step-by-step explanation:

1) X^2 + 2x - 15

2) find two numbers that when its added it gives you +2 and when multiplied it gives you -15. Those numbers are 5 and -3

3) now replace the +2x with 5x-3x

your equation should now look like this

x^2 + 5x -3x -15

4) now group x^2 + 5x and -3x-15

5) find whats in common between the two groups and factor it out

it should look like this x(x+5) and -3(x+5)

and two binomial factors are (x-3) & (x+5)

based off of the options the CORRECT ANSWER IS B) (X-3)!!

DON"T KNOW WHY YOU DELETED MY ANSWER AND YOU DID NOT ASK FOR WORK,YOU ASKED FOR AN ANSWER.

Maurinko [17]3 years ago

6 0

X^2 + 2x - 15
(x - 3) (x + 5)
B. (x - 3)

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Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$