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gregori [183]
3 years ago
5

Complete the truth table.

Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

TTTTTTTFFFFFFFFTTTTTTTTFFFFFFFF

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Jonah has been saving for a video game. Last year it cost $28. This year it costs $36. Determine the percent of change.​
nata0808 [166]

Answer:

Where: 28 is the old value in 36 is the new value in this case we have a positive change increase of 28.571142857

6 0
3 years ago
A small fruit smoothie is 18 ounces while a large fruit smoothie is 21.96 ounces. The large fruit smoothie is what % larger
maksim [4K]

First, subtract 18 from 21.96. 

21.96 - 18 = 3.96 

That is the amount it was increased by. 

Now, to find the percent increase, divide 3.96 by 18. 

3.96 ÷ 18 = 0.21444

In percents, that is equal to 21.444%. 

The large fruit smoothie is 21.444% larger. 

8 0
3 years ago
Read 2 more answers
Find the total surface area of a cone whose radius is r/2 and slant height is 2l
Hunter-Best [27]
Total surface area of cone:  πrl + πr²

Assuming the bottom of the cone is closed.

r = r/2,  l = 2l

Total surface Area =  π*(r/2)*2l + π(r/2)²  =  πrl + πr²/4

Total Surface Area = πrl + πr²/4
3 0
4 years ago
After losing 22 lb in each of the first two
Pavel [41]

Answer:

Weight on 1 may = 104 lb

Step-by-step explanation:

Given:

Weight on last may = 110 lb

Weight gain for to week = 2 x 19 = 38 lb

Weight lose for to week = 2 x 22 = 44 lb

Find:

Weight on 1 may

Computation:

Weight on 1 may = Weight on last may - Weight gain for to week + Weight lose for to week

Weight on 1 may = 110 - 44 + 38

Weight on 1 may = 104 lb

4 0
3 years ago
Which statements are true about the interquartile range? Select all that apply. Subtract the lowest and highest values to find t
katen-ka-za [31]

Answer:

The correct options are:

Interquartile ranges are not significantly impacted by outliers.

Lower and upper quartiles are needed to find the interquartile range.

The data values should be listed in order before trying to find the interquartile range.


The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.

The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

6 0
3 years ago
Read 2 more answers
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