2. Are these ratios equal? 6:10 and 5:20

Mathematics

2 answers:

defon3 years ago

6 0

The answer is no You’re welcome

Step2247 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

Think of it like this. 6/10 is 60% and 5/20 is 25%. These two values aren't the same.

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Adele Swam the length of the pool in 32.56 seconds. Alexandria swam the length of the pool in 29.4 seconds. How many seconds fas

Sati [7]

Answer

Find out how many seconds faster has Alexandria's time then Adele's time .

To proof

Let us assume that seconds faster has Alexandria's time then Adele's time be x.

As given in the question

Adele Swam the length of the pool in 32.56 seconds. Alexandria swam the length of the pool in 29.4 seconds.

Than the equation becomes

x = 32.56 - 29.4

x = 3.16 seconds

Therefore the 3.16 seconds faster has Alexandria's time then Adele's time .

Hence proved

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3 years ago

Which of the following is an example of a subset? The number of IT employees out of all employees working in an office of Google

marta [7]

Answer:

The number of IT employees out of all employees working in an office of Google

Step-by-step explanation:

The answer is the first one, because the rest Just describes a group of People, a subset is a part of a larger group of related things, while the others describes just a group of people, the first one which is the answer describes a group of people that's part of a larger group of people,

The subset is the IT employees working in an office for Google

whIle the main set is All employees working in an office of Google

4 0

3 years ago

Complex number Exercise 1.1 1. (_1)23/2

givi [52]

Answer:

Step-by-step explanation:

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3 years ago

On Halloween, a man presents a child with a bowl containing eight different pieces of candy. He tells her that she may have thre

likoan [24]

Answer:

$56$ choices

Step-by-step explanation:

We know that we'll have to solve this problem with a permutation or a combination, but which one do we use? The answer is a combination because the order in which the child picks the candy does not matter.

To further demonstrate this, imagine I have 4 pieces of candy labeled A, B, C, and D. I could choose A, then C, then B or I could choose C, then B, then A, but in the end, I still have the same pieces, regardless of what order I pick them in. I hope that helps to understand why this problem will be solved with a combination.

Anyways, back to the solving! Remember that the combination formula is

$_nC_r=\frac{n!}{r!(n-r)!}$ , where n is the number of objects in the sample (the number of objects you choose from) and r is the number of objects that are to be chosen.