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3 years ago

Evaluate this expression for a = 3 and b = 4.

Mathematics

1 answer:

Vladimir79 [104]3 years ago

8 0

I think it’s A I hope it helps

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Factor 16x^2 + 49. Check your work.

Shtirlitz [24]

Answer:

$16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

Step-by-step explanation:

Given : Expression $16x^2+49$

To find : Factor the expression ?

Solution :

The given expression is a quadratic function $y=ax^2+bx+c$ the solution is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing with general form,

a=16, b=0, c=49

Substitute in the formula,

$x=\frac{-0\pm\sqrt{0^2-4(16)(49)}}{2(16)}$

$x=\frac{\pm\sqrt{-3136}}{32}$

$x=\frac{\pm56i}{32}$

$x=\frac{56i}{32},\frac{-56i}{32}$

$x=\frac{7i}{4},\frac{-7i}{4}$

Factors are $(x-\frac{7i}{4}),(x+\frac{7i}{4})$

Therefore, $16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

4 0

4 years ago

10 POINTS AND BRAINLIEST<br> Please answer all 3 questions attached correctly.

lana66690 [7]

Answer:

#1. Identity #2. 0 #3. No solution

Step-by-step explanation:

#1.

5y + 2 = (1/2)(10y+4)

5y + 2 = 5y + 2

This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).

#2.

0.5b + 4 = 2(b+2)

0.5b + 4 = 2b + 4

0.5 b - 2b = 0

b = 0

#3.

-3x + 5 = -3x + 10

This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.

5 0

4 years ago

X+y+(y-2)=60,1/2(x)(y-2)=120 what is x and y

Rudiy27

I think is this hopefully this helps