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3 years ago

Find x. (Use pic for more info)

Mathematics

1 answer:

V125BC [204]3 years ago

8 0

Answer:

x=75

Step-by-step explanation:

Hey There!

If you didn't know the exterior angle of a triangle is equal to the sum of the opposite interior angles of a triangle

So essentially what I'm saying is that

2x-5=70+x

step 1 add 5 to each side

-5+5 cancels out

70+5=75

now we have

2x=70+x

step 2 subtract x from each side

x-x cancels out

2x-x=x

we're left with

x=75

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Answer:

The speed of the aircraft is 126.667 miles per hour.

Step-by-step explanation:

Let suppose that aircraft travels at constant speed. From Mechanical Physics, we understand speed as travelled distance divided by time. In this case, the absolute speed of the aircraft is the sum of wind speed and speed of the aircraft relative to wind. That is:

Tailwind (Wind flows in the same direction of aircraft)

$t = \frac{s_{T}}{v_{W,T}+v_{A/W,T}}$ (Eq. 1)

Headwind (Wind flow in the direction opposite to aircraft)

$t = \frac{s_{H}}{v_{W,H}+v_{A/W,H}}$ (Eq. 2)

Where:

$s_{T}$ , $s_{H}$ - Travelled distances on tailwind and headwind conditions, measured in meters.

$v_{W,T}$ , $v_{W,H}$ - Tailwind and headwind speeds, measured in meters per second.

$v_{A/W,T}$ , $v_{A/W,H}$ - Relative speeds of aircraft relative to tailwind and headwind, measured in meters per second.

We proceed to equalize both expressions to eliminate time:

$\frac{s_{T}}{v_{W,T}+v_{A/W,T}} = \frac{s_{H}}{v_{W,H}+v_{A/W,H}}$ (Eq. 3)

If we know that $s_{T} = 360\,mi$ , $s_{H} = 300\,mi$ , $v_{W,T} = 10\,\frac{mi}{h}$ , $v_{W,H} = -10\,\frac{mi}{h}$ and $v_{A/W,T} = v_{A/W,H}$ , then: