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max2010maxim [7]

3 years ago

5

Which representation of a transformation on a coordinate grid does not preserve congruence? A (x,y) → (x,-Y) B (x, y) + (x + 7,

y + 7) 1 C (x,y) → (5x7Y) , x D (x,y) → (y, -x)

1 answer:

tigry1 [53]3 years ago

4 0

Answer:

(x,y) --> (1/7x, 1/7y)

Step-by-step explanation:

You might be interested in

If (a+10) and (a+20)are supplementary angles,find them

motikmotik

Given:

(a+10) and (a+20) are supplementary

To find:

Each angle

Steps:

if 2 angles are supplementary that means they add up to 180°

(a + 10) + (a + 20) = 180

a + 10 + a + 20 = 180

2a + 30 = 180

2a = 180 - 30

2a = 150

a = 150/2

a = 75°

Now let's find value of each angle,

a + 10 = 75 + 10

= 85°

a + 20 = 75 + 20

= 95°

Therefore, the value of each angle is 85° and 95° respectively

Happy to help :)

If you need any help feel free to ask

4 0

3 years ago

What is the solution to the equation?

jekas [21]

Answer: -2 and -7 i think

7 0

3 years ago

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Mark drew two lines that form a right angle What words describe the lines that Mark Drew

Anni [7]

The lines that Mark drew are perpendicular.

4 0

4 years ago

What’s the compound inequality for this??

MariettaO [177]

Answer:

-2 < x<4

Step-by-step explanation:

We have open circles and -2 and 4 so we don't include those numbers

The line is in between so the x is in between

-2 < x<4

3 0

3 years ago

HELPPPP<br> please help me answer this question-

erik [133]

Answer:

$\displaystyle GH = 2 \sqrt{30}$

$\displaystyle FH = 2 \sqrt{10}$

$\displaystyle m \angle G = {30}^{ \circ}$

Step-by-step explanation:

<h3>QUESTION-2:</h3>

we are given a right angle triangle

it's a 30-60-90 triangle of which FH is the shortest side

remember that,in case of 30-60-90 triangle the the longest side is twice as much as the shortest side thus

our equation is

$\displaystyle 2FH=4\sqrt{10}$

divide both sides by 2

$\displaystyle\frac{2FH}{2}= \frac{ 4 \sqrt{10} }{2}$

$\displaystyle FH =2 \sqrt{10}$

<h3>Question-1:</h3>

in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle

as we want to figure out GH we'll use sin function

remember that,

$\displaystyle \sin( \theta) = \frac{opp}{hypo}$

let our opp, hypo and $\theta$ be GH, 4√10 and 60° respectively

thus substitute:

$\displaystyle \sin( {60}^{ \circ} ) = \frac{GH}{4 \sqrt{10} }$

recall unit circle:

$\displaystyle \frac{ \sqrt{3} }{2} = \frac{GH}{4 \sqrt{10} }$

cross multiplication:

$\displaystyle 2 GH = 4 \sqrt{10} \times \sqrt{3}$

simplify multiplication:

$\displaystyle 2 GH = 4 \sqrt{30}$

divide both sides by 2:

$\displaystyle GH = 2 \sqrt{30}$

<h3>QUESTION-3:</h3>

Recall that, the sum of the interior angles of a triangle is 180°

therefore,

$\displaystyle m \angle G + {60}^{ \circ} + {90}^{ \circ} = {180}^{ \circ}$

simplify addition:

$\displaystyle m \angle G + {150}^{ \circ} = {180}^{ \circ}$

cancel 150° from both sides

$\displaystyle m \angle G = {30}^{ \circ}$

6 0

3 years ago

Read 2 more answers